rew wrote:Your pencil has finite thickness. Your compass is not perfect, you have to visually set it to the right width. My calculator can EASILY outperform your not 100% accurate drawings

Yes but use an infinitely fine pencil & perfect compass & use the same geometric steps to make the same drawing and the drawing will EASILY outperform the not 100% accurate calculator [which with decimal numerals must "round" all output decimals to the nearest decimal digit -- eternally preventing 100% accuracy in the case of decimal representation of the square root of 3 without infinite paper or display screen mass]

rew wrote:Yes, but your simple: less copper, same KV motor will not have the same wattage.

Both of the last wye examples had different copper volume but yet had the same resistance so I would disagree on the basis of: same resistance with same applied voltage through ohm's law results in the same amps & wattage. [ W = I^2R ] <- same amps, same resistance [ & conductance ], same applied voltage, same electrical wattage

& kv = rpm/v peak [not V RMS]-- kv is measured from peak v not rms v therefore any kv measurement by definition must occur at & assume 100% duty cycle.

any theoretically infinitely precise decimal-based calculator would still require infinite display screen volume & therefore infinite physical volume to display the decimal equivalent of the square root of 3 -- but with a theoretically infinitely precise compass - any arbitrarily small volume may be used to represent the relative distance lengths of "1" & the "square root of 3" with infinite accuracy and precision [arbitrarily small -- not infinite -- volume necessary] -- causing the theoretically infinitely precise compass to surpass the inifinitely precise calculator in utility to volume ratio when representing "irrational lengths" with "infinite precision."

rew wrote:KV = Constant(motor) * C(termination) * turns.

C(termination) is 1 for Y or sqrt(3) for delta wiring.