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by devin
18 Sep 2017, 20:39
Forum: General
Topic: Watt Control Via Duty Cycle Control?
Replies: 14
Views: 1050

Re: Watt Control Via Duty Cycle Control?

Here is a single formula to obtain desired duty cycle from desired electrical wattage , winding resistance, present back emf V, and present pack voltage: A= XX.XXXA = Battery Amps B= XX.XXXA = Motor Amps C= 54.795% Duty Cycle D= 22.22222V = Present Back Emf V E= XX.XXXV = Effective PWM Voltage F= 0....
by devin
18 Sep 2017, 20:21
Forum: General
Topic: Watt Control Via Duty Cycle Control?
Replies: 14
Views: 1050

Re: Watt Control Via Duty Cycle Control?

Here is a single formula to obtain desired motor amps from desired electrical wattage , winding resistance, present back emf V: A= XX.XXXA = Battery Amps B= 39.246A = Motor Amps C= XX.XXX% Duty Cycle D= 22.22222V = Present Back Emf V E= XX.XXXV = Effective PWM Voltage F= 0.083ohm = Winding Resistanc...
by devin
18 Sep 2017, 19:36
Forum: General
Topic: Watt Control Via Duty Cycle Control?
Replies: 14
Views: 1050

Re: Watt Control Via Duty Cycle Control?

Here is a single formula to obtain desired motor amps from desired electrical wattage , winding resistance, motor kv and present rpm: A= XX.XXXA = Battery Amps B= 39.246A = Motor Amps C= XX.XXX% Duty Cycle D= XX.XXXV = Present Back Emf V E= XX.XXXV = Effective PWM Voltage F= 0.083ohm = Winding Resis...
by devin
18 Sep 2017, 18:35
Forum: General
Topic: Watt Control Via Duty Cycle Control?
Replies: 14
Views: 1050

Re: Watt Control Via Duty Cycle Control?

Here is a single formula to obtain desired duty cycle from desired electrical wattage , winding resistance, pack voltage, motor kv and present rpm: A= XX.XXXA = Battery Amps B= XX.XXXA = Motor Amps C= 54.795% Duty Cycle D= XX.XXXV = Present Back Emf V E= XX.XXXV = Effective PWM Voltage F= 0.083ohm =...
by devin
18 Sep 2017, 14:49
Forum: General
Topic: Watt Control Via Duty Cycle Control?
Replies: 14
Views: 1050

Re: Watt Control Via Duty Cycle Control?

With A= 10A = Battery Amps, B= 50A = Motor Amps, C= 20% = Duty Cycle, D= 5V = Present Back Emf V, E= 10V = Effective PWM Voltage F= 0.1ohm = Winding Resistance, G= 50V = Pack Voltage, H= 500W = Desired Wattage, I= 100kv = Motor KV, J= 500rpm = Present RPM It seems like half of your 500W is lost in ...
by devin
18 Sep 2017, 04:12
Forum: General
Topic: Watt Control Via Duty Cycle Control?
Replies: 14
Views: 1050

Re: Watt Control Via Duty Cycle Control?

^I think it's correct.... A= 10A = Battery Amps B= 50A = Motor Amps C= 20% = Duty Cycle D= 5V = Present Back Emf V E= 10V = Effective PWM Voltage F= 0.1ohm = Winding Resistance G= 50V = Pack Voltage H= 500W = Desired Wattage I= 100kv = Motor KV J= 500rpm = Present RPM A=H/G & D=(1/I)*J & E=(...
by devin
17 Sep 2017, 23:17
Forum: General
Topic: Watt Control Via Duty Cycle Control?
Replies: 14
Views: 1050

Re: Watt Control Via Duty Cycle Control?

^I think I made a mistake & this is actually the correct formula: ----------- Watt Control Via Duty Cycle Control? ----------- Could it be possible to implement wattage control for desired electrical wattage at all physically possible RPMs via duty cycle control? ----------- Where: A=Battery Amp...
by devin
17 Sep 2017, 22:03
Forum: General
Topic: Power Limiting instead of Current Limiting
Replies: 25
Views: 1487

Re: Power Limiting instead of Current Limiting

Possible solution?

Topic: "Watt Control Via Duty Cycle Control?" - http://vedder.se/forums/viewtopic.php?f=6&t=1572
by devin
17 Sep 2017, 21:59
Forum: General
Topic: Watt Control Via Duty Cycle Control?
Replies: 14
Views: 1050

Watt Control Via Duty Cycle Control?

Watt Control Via Duty Cycle Control ------------------------------ Could it be possible to implement wattage control for desired electrical wattage at all physically possible RPMs via duty cycle control? edited: the following formula is not valid, i've posted the corrected formula in a later post......
by devin
16 Sep 2017, 20:26
Forum: General
Topic: "Peak Efficiency" Control Mode?
Replies: 108
Views: 8485

Re: "Peak Efficiency" Control Mode?

Suppose things are not frictionless, but there is a constant drag-force . Now we might want to travel 1km. and the firiction might be 10N. This costs us an extra A in current to overcome. How does this change the strategy of "as little current as possible ? If the rider chooses a higher final ...

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